x^2-1.6x+0.5084=0

Solution for x^2-1.6x+0.5084=0 equation:

x^2-1.6x+0.5084=0

a = 1; b = -1.6; c = +0.5084;
Δ = b2-4ac
Δ = -1.62-4·1·0.5084
Δ = 0.5264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{0.5264}}{2*1}=\frac{1.6-\sqrt{0.5264}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{0.5264}}{2*1}=\frac{1.6+\sqrt{0.5264}}{2}
$